acrosstheuniverse said – Thu, 05 Jun 2008 19:28:26 -0000 ( Link )
This is a forum where you can ask about difficult trivia you`ve had trouble with, or you can discuss other GMAT related topics here.
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Questions about GMAT Specifics and Problems (Discussion)
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koustabhdolui said – Thu, 05 Jun 2008 19:37:10 -0000 ( Link )
GMAT- Data Sufficiency Q#192: Is x an integer? 1. x2 is an integer 2. x(1/2) is an integer Answer Choices Is correct? Answer Choices • A. Statement 1 ALONE is sufficient, but statement 2 alone is not sufficient • B. Statement 2 ALONE is sufficient, but statement 1 alone is not sufficient. • C. BOTH statements TOGETHER are sufficient, but NEITHER statement alone is sufficient. Incorrect D. EACH statement ALONE is sufficient • E. Statements 1 and 2 TOGETHER are NOT sufficient
Isn’t D the correct option here?
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koustabhdolui said – Thu, 05 Jun 2008 20:59:43 -0000 ( Link )
GMAT- Data Sufficiency Q#161: Is a=b? 1. a+b < 0 2. ab < 0 Answer Choices Is correct? Answer Choices • A. Statement 1 ALONE is sufficient, but statement 2 alone is not sufficient • B. Statement 2 ALONE is sufficient, but statement 1 alone is not sufficient. • C. BOTH statements TOGETHER are sufficient, but NEITHER statement alone is sufficient. • D. EACH statement ALONE is sufficient Incorrect E. Statements 1 and 2 TOGETHER are NOT sufficient
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koustabhdolui said – Thu, 05 Jun 2008 21:00:01 -0000 ( Link )
I think E is the answer…......
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koustabhdolui said – Fri, 06 Jun 2008 09:39:01 -0000 ( Link )
GMAT- Data Sufficiency Q#182: n is a positive integers. Is x – y at least twice as big as (3n) – (2n)? 1. x=2(n+1) and y=3(n+1) 2. n=3 Answer Choices Is correct? Answer Choices • A. Statement 1 ALONE is sufficient, but statement 2 alone is not sufficient • B. Statement 2 ALONE is sufficient, but statement 1 alone is not sufficient. Incorrect C. BOTH statements TOGETHER are sufficient, but NEITHER statement alone is sufficient. • D. EACH statement ALONE is sufficient • E. Statements 1 and 2 TOGETHER are NOT sufficient
Isn’t it C there?
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koustabhdolui said – Fri, 06 Jun 2008 09:58:20 -0000 ( Link )
GMAT- Quantitative Section Q#104: I have 2 cases of magnets. Each case contains p packages and each package contains e envelopes, each with 5 magnets inside. How many magnets do I have? Answer Choices Is correct? Answer Choices • e/20p • 20e/p • 20p/e • 20/pe Correct 20pe
But isn’t the answer 10pe?
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koustabhdolui said – Fri, 06 Jun 2008 10:03:39 -0000 ( Link )
GMAT- Quantitative Section Q#142: Which of the following numbers is not a square of an integer? Answer Choices Is correct? Answer Choices • 36 • 36/4 Incorrect 41-25 • Sqrt(Sqrt(1)) • Sqrt(64)
How????? root of 64=8
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oLahav said – Fri, 06 Jun 2008 13:48:18 -0000 ( Link )
Ok, one by one:
182: Using statement 1 alone, x – y equals 2 ^ (n+1) – 3 ^ (n+1), which in turn equals 2(2 ^ n) – 3(3 ^ n). This is greater than 2(2 ^ n) – 2(3 ^ n) which is therefore less than 2( (3 ^ n) – (2 ^ n)). So 1 is sufficient, and 2 clearly isn’t as it says nothing about x and y. That’s why it’s A.
104: You’re right, that one is a mistake, I’ve corrected it.
142: You’re right, the root of 64 is 8. But 8 is the square of root 8, which is 2root2, which is not an integer. All the other ones are squares of integers- 6, 3, 4 and 1.Hope this helps, and thanks for correcting my mistake!
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koustabhdolui said – Fri, 06 Jun 2008 14:47:21 -0000 ( Link )
GMAT- Data Sufficiency Q#62: Is the average of x, y and z equal to 7? 1. 3(a+b+c)=66 2. 2(a+b+c)=24 Answer Choices Is correct? Answer Choices • A. Statement 1 ALONE is sufficient, but statement 2 alone is not sufficient • B. Statement 2 ALONE is sufficient, but statement 1 alone is not sufficient. • C. BOTH statements TOGETHER are sufficient, but NEITHER statement alone is sufficient. • D. EACH statement ALONE is sufficient Incorrect E. Statements 1 and 2 TOGETHER are NOT sufficient
here’s no x,y,z!!!! in the question…......
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koustabhdolui said – Fri, 06 Jun 2008 14:56:30 -0000 ( Link )
I love this section the trivia…...so much to know
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koustabhdolui said – Fri, 06 Jun 2008 15:56:33 -0000 ( Link )
Nope what’s that?
Math SATs- more Trig: My triangle has sides 2, 2, 9. What kind of triangle is it?
Isosceles • Right-angled • No special kind • Equilateral • Both right-angled and isoscelesSir,the triange is not formed here…..2+2<9
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acrosstheuniverse said – Fri, 06 Jun 2008 16:13:14 -0000 ( Link )
Koustabhdolui, check out Mrs. Hubfellow’s Trivia Contest ! You could win an iPod simply by answering the most trivia, which you seem to be working great on so far!
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koustabhdolui said – Mon, 09 Jun 2008 05:53:07 -0000 ( Link )
Math SATs- Trigonometry: Say I have a triangle with one side of length 7, the angle across from it of size 30 degrees, and another angle of size 100 degrees. What are the other two sides of the triangle? Answer Choices Is correct? Answer Choices Incorrect Can’t be calculated with the information given. • 13.8, 10.7 • 5.2, 16.7 • 15.4, 12.8 • 13.8, 6.7
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koustabhdolui said – Mon, 09 Jun 2008 10:43:31 -0000 ( Link )
GMAT- Quantitative Section Q#35: In a certain office, 70% of workers are female. If 60% of females and 80% of males in the office are going to attend a business conference, what percentage of all workers won’t be attending the conference? Answer Choices
16% 7% 8% 12% 10%
The ans is 34%
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oLahav said – Mon, 09 Jun 2008 13:51:46 -0000 ( Link )
For the trig question- The answer can be calculated, so it’s not A.
You have to use the sine law here, which you can do since you have one angle and a side across of it. So you say x/(sin 100) = 7/(sin 30) and solve for x, and then do the same for the other side only with the right degree (which would be 180-30-100=50). Look at the sine law section here for more info on that.You’re right about the office question though, I’ll correct it to reflect the right answer. Thanks.
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koustabhdolui said – Mon, 09 Jun 2008 17:20:53 -0000 ( Link )
Yes you are right I missed out 180-30-100=50 this step….:(
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koustabhdolui said – Fri, 20 Jun 2008 15:50:04 -0000 ( Link )
GMAT- Data Sufficiency Q#81: I have a set of integers S, which contains 7 and other numbers. Is every positive multiple of 7 in my set? 1. For every number x in S, x+7 is in S. 2. For every number x is S, 7x is in S. Answer Choices Is correct? Answer Choices • A. Statement 1 ALONE is sufficient, but statement 2 alone is not sufficient • B. Statement 2 ALONE is sufficient, but statement 1 alone is not sufficient. • C. BOTH statements TOGETHER are sufficient, but NEITHER statement alone is sufficient. Incorrect D. EACH statement ALONE is sufficient • E. Statements 1 and 2 TOGETHER are NOT sufficient
I am bck Oren with my questions…...
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koustabhdolui said – Fri, 20 Jun 2008 15:51:46 -0000 ( Link )
Math SATs #145- easy: In my triangle, two sides are equal and perpendicular, and the other sides is sqrt(18). Find the area of the triangle. Answer Choices Is correct? Answer Choices • 9 • 3 Incorrect 5 • 12 • 18
Here’s another one….......the answer is 4.5
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koustabhdolui said – Fri, 20 Jun 2008 15:54:29 -0000 ( Link )
I have another question…......in a trivia question it was asked that I have a set S whether it contains all multiples of 7…......
I.if x is present in S x+7 is there II.if x is present in the set 7x is present too.
Is’nt the answer Each statement is sufficient?
It was given I is sufficient whereas II is not…......
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koustabhdolui said – Fri, 20 Jun 2008 17:57:48 -0000 ( Link )
That was really a tricky one…....I didnt think about the fact whether any integer other than 7 can be present…. :-)
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koustabhdolui said – Fri, 20 Jun 2008 18:19:01 -0000 ( Link )
GMAT- Quantitative Section Q#18: if x is not 1/3, then (6(x2)-10x+4)/(3x-1) is what? Answer Choices Correct Choice 2x-1 3x-7 3x+1 3x+4 2x+4
Here 6x2-10x+4 when factorised gives (3x-2)(2x-2)
So I dont get a factor 3x-1…....
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koustabhdolui said – Sun, 22 Jun 2008 18:10:55 -0000 ( Link )
Math SATs- more Sequences and Series: I have a sequence: 3, 15, 6, -7, ... . What would be the corresponding first 4 terms of the series based on this sequence? Answer Choices Is correct? Answer Choices Incorrect 3, 15, 6, -7 • 0, 3, 6, 9 • -7, 3, 6, 15 • 3, 18, 24, 17 • 3, 15, 18, 6
I did not understand this…..
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oLahav said – Mon, 23 Jun 2008 13:54:42 -0000 ( Link )
This lesson details sequences and series more thoroughly.
In short terms though, a series means the sum of all the terms up to and including the current term. So the first term of the series would just be the sum of just the first term of the sequence: 3. The second term would equal the sum of the first and second terms of the sequence: 3+15=18. The third would be 3+15+6=24, etc.
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koustabhdolui said – Wed, 25 Jun 2008 05:26:48 -0000 ( Link )
GMAT- Quantitative Section Q#107: My function passes through (1,2), (2,1), and (4,y) and is symmetric with respect to the line x=3. What’s y? Answer Choices Is correct? Answer Choices • 2 Incorrect 2.5 • 1.5 • 1 • 0.5
I could not understand
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koustabhdolui said – Wed, 25 Jun 2008 16:20:01 -0000 ( Link )
That is what GMAT is all about.The damn tricks…..
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koustabhdolui said – Wed, 25 Jun 2008 17:42:24 -0000 ( Link )
Quantitative Section Q#156: I have 100 cookies. 60 of my cookies have chocolate chips and 70 of them have peanut butter. If at least 20 cookies have neither chocolate chips nor peanut butter, the number of cookies that have both can be any number between:
What is the general method of solving these kind of problems?
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oLahav said – Wed, 25 Jun 2008 18:17:32 -0000 ( Link )
First of all, let’s say you have 20 cookies with neither. Then 80 cookies have either cc or pb or both. Let B be the number of cookies with both, then 80=cc+pb-B and then B=60+70-80=50. This is the minimum number of cookies with both. The maximum is easy- you know that only 60 cookies have cc, so if they all have pb as well you’d have 60 cookies with both, and there’s no way you can have any more of that. That’s your answer- 50 and 60.
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koustabhdolui said – Sat, 28 Jun 2008 18:55:28 -0000 ( Link )
Math SATs- more of those Sets, Modules and Ratios: I’m a baseball couch now. I have 30 guys in my team, out of which 2 are good at both serving the ball and hitting it with the bat, 22 are good at hitting it with their bats and a total of 7 are good at serving it. How many people should I kick off the team since they’re not good at either thing? Answer Choices Is correct? Answer Choices • 5 • 3 • 6 • 0 Incorrect 2
I think the answer is 1
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koustabhdolui said – Sun, 29 Jun 2008 03:49:07 -0000 ( Link )
1. Sentence Completion: Fill in the blank(s) by choosing the best word or set of words that fits within the context of the whole sentence.
When looking at the child, all I could think of was the tragedy he must feel being in ____ poverty.
concealed abstract fermented abjectCorrect answer is not given.I went for abject….
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koustabhdolui said – Sat, 05 Jul 2008 08:45:01 -0000 ( Link )
GMAT Prep- Quantitative Section #207: What is the value of \sqrt{\sqrt{16} – \sqrt{\frac{361}{625}}} ?
47/25 19/25 13/25 8/5 4/5Isn’t the answer 9/5
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koustabhdolui said – Wed, 09 Jul 2008 14:57:07 -0000 ( Link )
It happens,don’t be sorry .You’ve created 600+ questions in the Trivia with a 10-15 errors.Probability of a mistake .025!! :-)
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oLahav said – Wed, 16 Jul 2008 20:56:08 -0000 ( Link )
Since the t factor is squared, the ball drops more length with each second that passes. So in the first second it drops a bit, then it drops more, then in the final second it will drop the most. That’s why we can’t just plug in t=2, because dropping the ball for 2 seconds isn’t the same as dropping the ball for 3 seconds first then for 2 more seconds.
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amitspruce said – Wed, 30 Jul 2008 04:20:10 -0000 ( Link )
Some of the people in Town X are left-handed, some > are tall, some are both, and some are neither. In > Town Y, three times as many people are left-handed > as are left-handed in Town X, three times as many > people are tall as are tall in Town X, three times > as many people are both as are both in Town X, but > no one is neither. If the total number of people in > Town X is four times greater than the total number > of people in Town Y, which of the following could be > the number of people in Town X who are neither > left-handed nor tall? > > (A) 23 > (B) 39 > (C) 72 > (D) 143 > (E) 199
Can anyone answer this question ??
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amitspruce said – Wed, 30 Jul 2008 11:19:20 -0000 ( Link )
Set B has three positive integers with a median of 9. If the largest possible range of the three numbers is 19, given a certain mean, what is that mean? (A) 22 (B) 10 (C) 9.6 (D) 9
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amitspruce said – Wed, 30 Jul 2008 11:24:12 -0000 ( Link )
a, b, and c are integers and a < b < c. S is the set of all integers from a to b, inclusive. Q is the set of all integers from b to c, inclusive. The median of set S is (3/4)b. The median of set Q is (7/8)c. If R is the set of all integers from a to c, inclusive, what fraction of c is the median of set R?
(A) 3/8 (B) 1/2 (C) 11/16 (D) 5/7 (E) 3/4
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amitspruce said – Wed, 30 Jul 2008 11:25:13 -0000 ( Link )
any takers for the above questions ??? please post ur reply ??
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amitspruce said – Wed, 30 Jul 2008 17:36:54 -0000 ( Link )
If the average of 5 data points is 3.5, which new data point would result in the smallest standard deviation?
A. 2 B. 2.5 C. 3 D. 3.5 E. 4
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amitspruce said – Wed, 30 Jul 2008 18:12:27 -0000 ( Link )
why cant we have 3 or 3.5 as the answer instead of 4? The whole idea is to have a number closer to mean, so we can have 3 too as the answer and for that matter 3.5, which wont affect the current SD at all. Please clarify, as i am not able to visualize the correct reasoning behind the choice.
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amitspruce said – Wed, 30 Jul 2008 18:26:31 -0000 ( Link )
oh i am sorry !! i thought u marked the answer as 4 :) .. thanks for all your clarifications !!!!
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amitspruce said – Fri, 15 Aug 2008 19:46:01 -0000 ( Link )
Tanya prepared 4 different letters to be sent to 4 different addresses. For each letter , she prepared an envelope with its correct address. If the 4 letters are to be put into the 4 envelopes at random, what is the probability that only I letter will be put into the envelope with its correct address ?
1. 1/24 2. 1/8 3. ¼ 4. 1/3 5. 3/8
If k is a positive integer, is k the square of an integer ?
1. k is divisible by 4 2. k is divisible by exactly four different prime numbers.
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oLahav said – Fri, 15 Aug 2008 20:00:13 -0000 ( Link )
For letter A in envelope A, we can have letter B in envelope C, C in D and D in B, or B in D, C in B and D in C- only 2 options out of 6 would work (6 because ordering the other 3 letters have 3!=6 options). Since it doesn’t matter which letter in the correct 1, I would think the answer should be 1/3, but I may be missing something, I’m not very good in combinatorics.
For the other question- 1 is insufficient (take a look at 8 vs. 16). 2 is also insufficient, clearly, as 2 * 3 * 5 * 7= 210 is not the square of an integer, but 210 ^ 2 = 44100 is. Together, it’s still not sufficient- we know 2 ^ 2 is a factor, but the other factors may or may not be to the power of 2. So I believe the answer is E.
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madhav singh said – Fri, 15 Aug 2008 20:04:05 -0000 ( Link )
WILL GO WITH THESE ANSWERS; PART A: 4. 1/3. PART B: INSUFFICIENT DATA
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madhav singh said – Fri, 15 Aug 2008 20:17:22 -0000 ( Link )
LET US SAY L1, L2, L3, L4 ARE FOUR DIFFERENT LETTERS. E1, E2, E3, E4 FOUR DIFFERENT ENVELOPES. CASE1. L1 GOES TO E1. NOW, WITH THIS CORRECT POSITION OF L1, LET US SEE WHAT COMBINATION ( WITH EVERY LETTER IN A DIFF. ENVELOPE) WE GET. L2: E3 OR E4 L3: E4 OR E2 L4:E2 OR E3 i.e. for a given correct ( L1 IS CORRECT), there are two ways of putting the other letters in an incorrect envelope hence, in total we get 8 ways ( two each for four of them ) hence P = 8/24 = 1/3
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madhav singh said – Fri, 15 Aug 2008 20:32:39 -0000 ( Link )
WE GET 24 IN THE DENOMINATOR, SINCE TOTAL NO. OF SAMPLE EVENTS WII BE P( 4,4) ,
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madhav singh said – Fri, 15 Aug 2008 20:49:53 -0000 ( Link )
thanks oLahav, i hope that i am correct, b’coz you are never sure with probability!!!!! we will wait for amit to confirm the answers.
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ssarwal said – Sat, 30 Aug 2008 17:18:46 -0000 ( Link )
I have a question here in one of the preparatory books, the answer to which I don’t quite understand: If s are t are positive integers such that s/t=64.12, which of the following could be the remainder when s is divided by t? The choices provided are:2/4/8/20/45.
The correct one is 45. Guess someone can help me with this..
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oLahav said – Tue, 09 Sep 2008 16:18:52 -0000 ( Link )
s/t = 64.12. So we already know that the quotient is 64, so we can write that s=64t + r, for some remainder r. Now, s/t=64.12, so then 64.12 = 64 + r/t if we substitute and divide by t. Then we get that r= 0.12 t, or t=r/0.12 = 25 r / 3. Since t is an integer, this means r has to be divisible by 3, and the only option that satisfies this condition is 45. Therefore, the answer is 45.
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Sureshbala said – Fri, 07 Nov 2008 12:00:28 -0000 ( Link )
Definitely, we are here exactly for the same job…Shoot us straight away…
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ssarwal said – Fri, 14 Nov 2008 04:51:52 -0000 ( Link )
Thanks a ton Sureshbala, it means a lot. Am writing data suff qn which i typically get stuck on: Qn 1. If n is a +ve integer & r is the remainder when 4+7n is divided by 3, what is the value of r? (1) n+1 is divisible by 3 (2) n>20
A. Statement 1 ALONE is sufficient, but statement 2 alone is not sufficient B. Statement 2 ALONE is sufficient, but statement 1 alone is not sufficient. C. BOTH statements TOGETHER are sufficient, but NEITHER statement alone is sufficient. D. EACH statement ALONE is sufficient E. Statements 1 and 2 TOGETHER are NOT sufficient
Qn 2. For every +ve integer n, the function h(n) is defined to be the product of all even integers fron 2 to n, inclusive.If p is the smallest prime factor of h(100)+1, then p is: (1)between 2 & 10 (2)between 10 & 20 (3)between 20 & 30 (4)between 30 & 40 (5) > 40 (Ans)
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Sureshbala said – Fri, 14 Nov 2008 19:17:01 -0000 ( Link )
Fine…let’s look at the first question.
We need to find the remainder when 7n + 4 is divided by 3.
From Statement (1), it is given given that n + 1 is divisible by 3.
So let n + 1 = 3k
Hence n = 3k – 1
Now 4n + 7 = 4 (3k – 1) + 7 = 12k + 3 = 3(4k + 1)
Hence 4n + 7 is clearly a multiple of 3. So when it is divided by 3, the remainder will be 0.
Thus Statement (1) alone is sufficient to answer this.
Clearly Statement (2) is alone not sufficient to answer this. For example if you take n = 21, the remainder will be 1 and for n = 23, the remainder will be 0.
Thus Statement (1) alone is sufficient whereas Statement (2) alone is NOT sufficient to answer this.
Let’s look at the second question.
First, let us calculate h(100)
Given
Now we will take out all the twos in this number. So it becomes
Now it is clear that every prime number less that 50 will divide h(100) exactly.
So we can conclude, since all the prime number less than 50 divides h(100), all the prime numbers less than 50 will not divided h(100) + 1 .
So the smallest prime number that divides h(100) + 1 must be definitely greater than 50.
I think your final choice must be greater than 50 and not 40.
Anyway, I hope that the concept is lucid.
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Sureshbala said – Tue, 18 Nov 2008 11:15:06 -0000 ( Link )
Ok..let’s look at the first one..
Stat(1): Slope of the line is -1/6
As you said using y = mx + c, the equation of the line will be 6y+x=c, where X-intercept is c and y-intercept is c/6 (this will be clear if you the equation 6y+x = c in the form of x/a + y/b =1)
Thus both the X and Y intercepts will have same sign (depending upon the sign of c)
So we can conclude that if both X and Y intercepts are positive the line will intersect the First Quadrant and if both X and Y intercepts are negative, the line will intersect the Third Quadrant.
So the given line will not intersect the Second Quadrant.
Hence Stat(1) is Sufficient.
Clear second statement alone is not sufficient.
Coming to your second question, I could not figure out the options as well as the question. Is it f[f(x)] = f(1-x)?
Anyway, please go through the Support Community and especially go through this lesson to type mathematical equations
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ssarwal said – Wed, 19 Nov 2008 01:41:11 -0000 ( Link )
Thank you Suresh, I went through the lesson it helped me to a great extent. Am taking the exam this Sat so am loaded with queries & you were the only one who seemed to respond, so I post to you. Hpoing its ok with you.
Qn 2 For which of the following functions f is f(x)=f(1-x) for all x?I guess it is indeed f[f(x)] = f(1-x) 2.f(x)=1- x^ 2 3.f(x)=x2 – (1-x)2 4.f(x)=x2(1-x)2 5. f(x)=x/1-x
Options: 1. f(x)=1-x- Actions
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Sureshbala said – Thu, 20 Nov 2008 10:56:31 -0000 ( Link )
Ok, now I am bale to figure out your options I guess…
Let us consider the question as f(x) = f(1-x)
Here are the options (that i understood from your code)
Now questions like these can be answered fast by plugging some values for x.
Let us take the value of x to be 1.
Now the given question is f(1) = f(0)
So go to the options and verify this condition.
From option 1. f(1) = 0 and f(0)= 1. So this is not the answer
From option 2. f(1) = 0 and f(0) = 1. So this is also not the answer.
From option 3. f(1) = 1 and f(0) = -1. Not the answer
From option 4. f(1) = 0 and f(0) = 0. Hence the answer.
You can leave out option 5, as it is not defined for x = 1.
So your answer is choice 4.
In fact you can also questions like these by substituting 1-x for x in the given options and then figure out the answer. But substituting values for x would be easy and fast.
In case, for the value of x taken by you if you are getting two options that satisfy the given condition, change the value of x and verify those two options with this new value of x and thus you will be able to figure out the correct answer.
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ssarwal said – Thu, 20 Nov 2008 12:33:48 -0000 ( Link )
Thanks a lot Suresh…I have one more All of the stocks on an over the counter market are designated by either a 4 letter or 5 letter code created by using 26 alphabets.wHICH OF THE FOLLOWING GIVES THE MAXIMUM # OF STOCKS that can be designated with these codes: (1) 2(265) (2) 26(264) (3) 27(264) (4) 26(265) (5) 27(26^5) I thought the answer to be option 2 however its 3. Pls help..
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Sureshbala said – Fri, 21 Nov 2008 07:05:05 -0000 ( Link )
Coming to Permutations & Combinations you should think in terms of practical life. Please keep aside the formula based approach.
Ok, let’s finish this….
It is clear that we can have 4 letter or 5 letter code.
Let us calculate the the total number of stocks with 4 letter codes and also the total number of stocks with 5 letter codes.
After that the maximum number of stocks will be the sum of the number of 4 letter codes and 5 letter codes.
Let’s calculate the stocks with 4 letter codes.
Now the first letter of the code can be anyone of the 26 alphabets.
Since repetition of the letters is permitted, each and other letter of the code also can be anyone of the 26 alphabets.
So, it’s something like we have a job consisting of 4 tasks of filling 4 places and it is clear that each task can be done in 26 ways. Hence our job can be done in
ways.
Thus we will have a total of
Similarly we will have a total of
stocks with 5 letter code.
Hence the maximum number of total stocks is
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ssarwal said – Fri, 21 Nov 2008 14:32:01 -0000 ( Link )
Thank you Sureshbala…Also would it be feasible for you to suggest some smart, quick kill techniques for Data Suff questions. I am not sure this is the right discussion forum, unless I am missing something there isn’t a seprate one for it.
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oLahav said – Thu, 25 Jun 2009 14:16:21 -0000 ( Flag Edit Link )
This is a trick question, most data sufficiency are.
If (x^2) is integer, x is not necessarily an integer. For example, if x is sqrt(2), then x ^ 2 would be 2, so it would be an integer, even though x is not an integer. However, if x is 5, x ^ 2 is still an integer and now x is an integer. So Statement A is insufficient to answer the problem.
Statement B is sufficient though- if sqrt(x) is an integer, x is a perfect square, so it’s an integer too under all circumstances.
And so, the answer should be B.
Hopefully that helps, let me know if you’re still unclear about it.