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percentage question (Question)

indianschoolofbusiness saidSat, 19 Sep 2009 10:19:45 -0000 ( Link )

At a certain university, 60% of the professors are women, and 70% of the professors are tenured. If 90% of the professors are women, tenured or both, then what percent of the men are tenured?

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  1. avinash rai saidWed, 23 Sep 2009 09:33:50 -0000 ( Link )

    the 2 statement implies that 40% r tenured hence 30% of the men are tenured of total 40% professors ans 75%

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  2. guptha4u saidWed, 23 Sep 2009 10:47:52 -0000 ( Link )

    n(AUB) = n(A)+n(B)-n(AB). 90= 60+70-n(AB). Hence 40% are women tenured. Therefore 30% are men tenured. The Answer is 30%.

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  3. deepa mittal saidThu, 24 Sep 2009 16:43:30 -0000 ( Link )

    As 60% of professors are women, men = 40%

    90% professors are either women or tenured or both

    Since we have a total of 60% women this leaves us with 90% – 60% = 30% who are tenured but not women, i.e. tenured men.

    Since we have a total of 40 men and 30 are tenured, there must be 10 who are not.

    Therefore answer = 30% / 40% = 75%

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  4. indianschoolofbusiness saidMon, 28 Sep 2009 15:50:48 -0000 ( Link )

    Women = 60% . Hence, men = 40% Now, 90% are women, tenured or both. This says that, 90% contains women who are tenured or not tenured and men who are tenured too. Therefore, the rest 10% is men who are not tenured. Now, fill in the table and get the answer.

    30 / 40 * 100 = 75%

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  5. guptha4u saidWed, 07 Oct 2009 11:37:26 -0000 ( Link )

    It will be like this. Men 30 10 40 Wom 40 20 60 Total 70 30 100

    Tenured    Non Tenured    Total

    30/40*100 = 75% is right answer

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