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problem solving (Question)
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vsatyaramesh said – Wed, 21 Oct 2009 07:39:04 -0000 ( Link )
This question does not seem to be worded correctly
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gopaljee5505 said – Wed, 21 Oct 2009 19:25:25 -0000 ( Link )
24 . first person can be taken in 4 ways, when one of the four members has been selected then the second member can be selected in 3 ways from among the remaining couples.similarly the last member can be selected in 2 ways and thus total number will be 4×3x2=24 ways
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patmi17 said – Fri, 23 Oct 2009 11:55:54 -0000 ( Link )
without any restriction 3 persons from 4 couples =8c3 =56 ways now all different people => 56 – no of ways a couple and a third person can be chosen =56-(4*6)=32 .......> 4 couples can be choosen in 4 ways and 3rd person can be choosen in 6 ways . ans =32.
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